A signal $V_{in} (t)$ shown is applied from $t = 0 \; \text{ms}$ to $t = 6 \; \text{ms}$ to the circuit shown. Given the initial voltage across the capacitor is $0.3 \; \text{V},$ and that the diode is ideal, the open circuit voltage $V_{out}(t)$ at $t = 5 \; \text{ms}$ is ___________
- $0.3 \; \text{V}$
- $0.6 \; \text{V}$
- $0.7 \; \text{V}$
- $1.0 \; \text{V}$