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GATE IN 2024 | Question-47

In the figure shown, the diode current is given by $I_{D}=I_{S} e^{\frac{\alpha V_{D}}{T}} \cdot V_{D}$ is the diode voltage in volts, $T$ is the absolute temperature in Kelvin, $\alpha=1.16 \times 10^{4} \mathrm{~K} / \mathrm{V}$, and $I_{S}=10^{-15} \mathrm{~A}$ is the saturation current. The dc current source, opamp and the resistors are ideal, and are assumed to be temperature independent. The change in the output voltage $\left(\mathrm{V}_{\text {out }}\right.$ ) per Kelvin change in temperature is $\mathrm{mV}$ (rounded off to one decimal place).

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