0 votes 0 votes The maximum value of the solution y(t) of the differential equation $y(t)+\ddot{y}(t)=0$ with initial conditions $\dot{y}(0)=1$ and $y(0)=1,$ for $t\underline{>}0$ is $1$ $2$ $\pi$ $\sqrt{2}$ Differential equations gate2013-in differential-equations + – Milicevic3306 asked Mar 25, 2018 • recategorized Mar 19, 2021 by Lakshman Bhaiya Milicevic3306 7.9k points answer See all 0 reply