An $N-$bit, $ADC$ has an analog reference voltage $V$. Assuming zero mean and uniform distribution of the quantization error, the quantization noise power will be:
- $\frac{V^2}{12(2^N-1)^2}$
- $\frac{V^2}{12(2^N-1)}$
- $\frac{V}{12(2^N-1)}$
- $\frac{V^2}{\sqrt{12} }$