0 votes 0 votes In the given figure angle $Q$ is a right angle, $PS:QS=3:1, RT:QT=5:2$ and $PU:UR=1:1$. If area of triangle $QTS$ is $20\; cm^2$, then the area of triangle $PQR$ in $cm^2$ is $\_\_\_\_\_\_\_\_\_\_\_.$ Quantitative Aptitude gate2015-in numerical-ability geometry triangles area + – Milicevic3306 asked Mar 26, 2018 • recategorized Mar 20, 2021 by Lakshman Bhaiya Milicevic3306 7.9k points answer See all 0 reply