0 votes 0 votes In the neighborhood of $z=1$, the function $f(z)$ has a power series expansion of the form $f(z)$ = $1$ + $(1-z)$ + $(1-z)^2+ \ldots$ Then $f(z)$ is $\frac{1}{z}$ $\frac{-1}{z-2}$ $\frac{z-1}{z+}$ $\frac{1}{2z-1}$ Analysis of complex variables gate2016-in analysis-of-complex-variables taylor-series + – Milicevic3306 asked Mar 26, 2018 • retagged Mar 20, 2021 by Lakshman Bhaiya Milicevic3306 7.9k points answer See all 0 reply