0 votes 0 votes If $x=\sqrt{-1},$ then the value of $x^x$ is $e^{-\pi/2}$ $e^{\pi/2}$ $x$ $1$ Calculus gate2012-in calculus functions complex-number + – Milicevic3306 asked Mar 25, 2018 • recategorized Mar 19, 2021 by Lakshman Bhaiya Milicevic3306 7.9k points answer See all 0 reply