0 votes 0 votes In the circuit shown below, the current through the inductor is $\frac{2}{1+j}\text{A}$ $\frac{-1}{1+j}\text{A}$ $\frac{1}{1+j}\text{A}$ $0\text{A}$ Others gate2012-in + – Milicevic3306 asked Mar 25, 2018 • edited Nov 19, 2020 by soujanyareddy13 Milicevic3306 7.9k points answer See all 0 reply