0 votes 0 votes The responsivity of the $\text{PIN}$ photodiode shown is $0.9\;A/W.$ To obtain $V_\text{out}$ of $-1\;\text{V}$ for an in optical power of $1\;\text{mW},$ the value of $R$ to be used is $0.9\;\Omega$ $1.1\;\Omega$ $0.9\;k\Omega$ $1.1\;k\Omega$ Others gate2012-in + – Milicevic3306 asked Mar 25, 2018 • edited Nov 19, 2020 by soujanyareddy13 Milicevic3306 7.9k points answer See all 0 reply
