For the circuit shown in the figure, the voltage and current expressions are
$v(t)=E_1\sin(\omega t)+E_3\sin(3\omega t)$ and $i(t)=I_1\sin(\omega t-\phi_1)+I_3\sin(3\omega t-\phi_3)+I_5\sin(5\omega t).$
The average power measured by the Wattmeter is
- $\frac{1}{2}E_1I_1\cos\phi_1$
- $\frac{1}{2}[E_1I_1\cos\phi_1+E_1I_3\cos\phi_3+E_1I_5]$
- $\frac{1}{2}[E_1I_1\cos\phi_1+E_3I_3\cos\phi_3]$
- $\frac{1}{2}[E_1I_1\cos\phi_1+E_3I_1\cos\phi_1]$