0 votes 0 votes Consider the differential equation $\frac{d^2y(t)}{dt^2}+2\frac{dy(t)}{dt}+y(t)=\delta(t)$ with $y(t)|_{t=0^-}=-2$ and $\frac{dy}{dt}|_{t=0^-}=0$. The numerical value of $\frac{dy}{dt}|_{t=0^+}$ is $-2$ $-1$ $0$ $1$ Differential equations gate2012-in differential-equations + – Milicevic3306 asked Mar 25, 2018 • recategorized Mar 19, 2021 by Lakshman Bhaiya Milicevic3306 7.9k points answer See all 0 reply