0 votes 0 votes The Laplace Transform representation of the triangular pulse shown below is $\frac{1}{s^2}[1+e^{-2s}]$ $\frac{1}{s^2}[1-e^{-s}+e^{-2s}]$ $\frac{1}{s^2}[1-e^{-s}+2e^{-2s}]$ $\frac{1}{s^2}[1-2e^{-s}+e^{-2s}]$ Differential equations gate2013-in differential-equations laplace-transform + – Milicevic3306 asked Mar 25, 2018 • recategorized Mar 19, 2021 by Lakshman Bhaiya Milicevic3306 7.9k points answer See all 0 reply