0 votes 0 votes The solution $x(t), t \geq 0$, to the differential equation $\ddot{x}=-k \dot{x}, k>0$ with initial conditions $x(0)=1$ and $\dot{x}(0)=0$ is $x(t)=2 e^{-k t}+2 k t-1$ $x(t)=2 e^{-k t}-1$ $x(t)=1$ $x(t)=2 e^{-k t}-k t-1$ Others gatein-2023 + – admin asked May 22, 2023 • edited Nov 22, 2023 by makhdoom ghaya admin 2.7k points answer See all 0 reply