0 0 votes The signal $\sin\left ( \sqrt{2\pi t} \right )$ is periodic with period $T=\sqrt{2\pi }$ not periodic periodic with period $T=2\pi$ periodic with period $T=4\pi ^{2}$ Signals and Systems gatein-2021 signals-and-systems + – Arjun 3.6k points answer 0 reply
