0 votes 0 votes The signal $\sin\left ( \sqrt{2\pi t} \right )$ is periodic with period $T=\sqrt{2\pi }$ not periodic periodic with period $T=2\pi$ periodic with period $T=4\pi ^{2}$ Others gatein-2021 + – Arjun asked Feb 19, 2021 • edited Mar 5, 2021 by soujanyareddy13 Arjun 2.9k points answer See all 0 reply