0 0 votes Consider the real-valued function $g(x)=\max \left\{(x-2)^2,-2 x+7\right\}$, where $x \in(-\infty, \infty)$. The minimum value attained by $g(x)$ is_____________(rounded off to one decimal place). Calculus gatein-2023 numerical-answers calculus maxima-minima + – admin 3.2k points answer 0 reply
0 0 votes Ans : 1.0g(x)=max{u(x),v(x)}, the minimum of g typically occurs at a point where the two functions cross (so their values are equal) provided that at that crossing the common value is as small as possible. legend_of_cse answered Aug 24, 2025 legend_of_cse 300 points comment Share ask related question 0 reply Please log in or register to add a comment.