2 2 votes A matrix $M$ is constructed by stacking three column vectors $v_{1}, v_{2}, v_{3}$ as$$ M=\left[\begin{array}{lll} v_{1} & v_{2} & v_{3} \end{array}\right]$$Choose the set of vectors from the following options such that $\operatorname{rank}(M)=3$.$v_{1}=\left[\begin{array}{l}1 \\ 0 \\ 1\end{array}\right], \quad v_{2}=\left[\begin{array}{r}0 \\ -1 \\ 0\end{array}\right], \quad v_{3}=\left[\begin{array}{r}1 \\ -1 \\ 1\end{array}\right]$$v_{1}=\left[\begin{array}{l}1 \\ 1 \\ 1\end{array}\right], \quad v_{2}=\left[\begin{array}{r}-1 \\ 0 \\ 1\end{array}\right], \quad v_{3}=\left[\begin{array}{l}0 \\ 0 \\ 0\end{array}\right]$$v_{1}=\left[\begin{array}{l}1 \\ 0 \\ 1\end{array}\right], \quad v_{2}=\left[\begin{array}{r}-1 \\ 0 \\ 1\end{array}\right], \quad v_{3}=\left[\begin{array}{r}1 \\ -1 \\ 1\end{array}\right]$$v_{1}=\left[\begin{array}{l}1 \\ 1 \\ 1\end{array}\right], \quad v_{2}=\left[\begin{array}{r}-1 \\ 1 \\ -1\end{array}\right], \quad v_{3}=\left[\begin{array}{r}0 \\ -1 \\ 0\end{array}\right]$ Linear Algebra gatein-2024 linear-algebra matrix-algebra rank-of-matrix + – admin 3.2k points answer 0 reply
0 0 votes Option 1 Notice: Column 1 = Column 3 So columns are dependent. ❌ Rank < 3 Option 2 Column 3 is the zero vector. A zero vector is always dependent. ❌ Rank < 3 Option 3 Let's compute the determinant: Since determinant ≠ 0, ✅ Rank = 3 Shrawani0702 answered Jul 29 Shrawani0702 200 points comment Share ask related question 0 reply Please log in or register to add a comment.