0 0 votes The value of the surface integral $\iint_{S}(2 x+z) \mathrm{d} y \mathrm{~d} z+(2 x+z) \mathrm{d} x \mathrm{~d} z+(2 z+y) \mathrm{d} x \mathrm{~d} y$ over the sphere $S: x^{2}+y^{2}+z^{2}=9$ is $72 \pi$ $144 \pi$ $36 \pi$ $432 \pi$ Calculus gatein-2025 calculus vector-calculus numerical-answers + – Shubham Sharma 2 1.5k points answer 0 reply
