Three parallel admittances $Y_{a}=-j 0.2 \mathrm{~S}, Y_{b}=0.3 \mathrm{~S}$, and $\quad Y_{c}=j 0.4 \mathrm{~S}$ connected in parallel with a voltage source $V_{s}=10 \angle 45^{\circ} \: \mathrm{V}$, draw a total current $I_{s}$ from the source. The currents flowing through each of these admittances are $I_{a}, I_{b}$, and $I_{c}$, respectively. Let $I=I_{b}+I_{c}$. The phase relation between $I$ and $I_{s}$ is
- $I$ leads $I_{s}$ by $19.44^{\circ}$
- $I$ lags $I_{s}$ by $19.44^{\circ}$
- $I$ leads $I_{s}$ by $33.69^{\circ}$
- $I$ lags $I_{s}$ by $33.69^{\circ}$
