0 0 votes The maximum value of the solution y(t) of the differential equation $y(t)+\ddot{y}(t)=0$ with initial conditions $\dot{y}(0)=1$ and $y(0)=1,$ for $t\underline{>}0$ is $1$ $2$ $\pi$ $\sqrt{2}$ Differential equations gate2013-in differential-equations numerical-answers + – Milicevic3306 7.9k points answer 0 reply
