Frequency of an analog periodic signal in the range of $5kHz-10kHz$ is to be measured with a resolution of $100Hz$ by measuring its period with a counter. Assuming negligible signal and transition delays the minimum clock frequency and minimum number of bits in the counter needed, respectively, are:
- $1\; MHz,\; 10-bits$
- $10\; MHz,\; 10-bits$
- $1\; MHz,\; 8-bits$
- $10\; MHz,\; 8-bits$