0 0 votes The output voltage of the ideal transformer with the polarities and dots shown in the figure is given by $NV_i\sin \omega t$ $-NV_i\sin \omega t$ $\frac{1}{N}V_i\sin \omega t$ $-\frac{1}{N}V_i\sin \omega t$ Electrical Circuits and Machines gate2015-in electrical-circuits-and-machines + – Milicevic3306 7.9k points answer 0 reply
