0 0 votes The bandgap in $eV$ of a semiconductor material required to construct an $LED$ that emits peak power at the wavelength of $620\;nm$ is $\_\_\_\_\_\_\_.$ (Plank constant $h=4.13567\times10^{-15}\;eV\;s$ and speed of light $c=2.998\times10^8\;m/s$). Analog Electronics gate2016-in numerical-answers analog-electronics physics + – Milicevic3306 7.9k points answer 0 reply
