0 0 votes A discrete- time signal x[n] = e$^{j(\frac{5\pi}{3})n}$ + e$^{j(\frac{\pi}{4})n}$ is down-sampled to the signal x${_d}[n]$ such that x${_d}[n]$ = x[4n]. The fundamental period of the down-sampled signal x${_d}[n]$ is $\_\_\_\_\_\_$. Signals and Systems gate2019-in numerical-answers signals-and-systems + – Arjun 3.6k points answer 0 reply