0 0 votes The responsivity of the $\text{PIN}$ photodiode shown is $0.9\;A/W.$ To obtain $V_\text{out}$ of $-1\;\text{V}$ for an in optical power of $1\;\text{mW},$ the value of $R$ to be used is $0.9\;\Omega$ $1.1\;\Omega$ $0.9\;k\Omega$ $1.1\;k\Omega$ Communication and Optical Instrumentation gate2012-in analog-electronics communication-and-optical-instrumentation numerical-answers + – Milicevic3306 7.9k points answer 0 reply
