0 0 votes The Fourier transform of a signal $h(t)$ is $H(j\omega)=(2\cos\omega)(\sin2\omega)/\omega.$ The value of $h(0)$ is $1/4$ $1/2$ $1$ $2$ Differential equations gate2012-in differential-equations fourier-transform + – Milicevic3306 7.9k points answer 0 reply
