0 0 votes Let $y[n]$ denote the convolution of $h[n]$ and $g[n]$, where $h[n]=(1/2)^n\;u[n]$ and $g[n]$ is a causal sequence. If $y[0]=1$ and $y[1]=1/2$, then $g[1]$ equals $0$ $1/2$ $1$ $3/2$ Signals and Systems gate2012-in signals-and-systems numerical-answers + – Milicevic3306 7.9k points answer 0 reply
