0 0 votes A $3 \times 3$ matrix $P$ with all real elements has eigenvalues $\dfrac{1}{4}, 1$, and $-2$. The value of $\mid P^{-1}\mid$ is $\_\_\_\_\_\_$ (rounded off to nearest integer). Linear Algebra gatein-2024 numerical-answers linear-algebra + – admin 3.2k points answer 0 reply
0 0 votes Given eigenvalues of $P$ are $1/4, 1, -2$. Determinant $|P| = (1/4) \times 1 \times (-2) = -0.5$. \\ We know $|P^{-1}| = 1 / |P|$. $|P^{-1}| = 1 / (-0.5) = -2$. Hira Thakur answered Jan 31 Hira Thakur 270 points comment Share ask related question 0 reply Please log in or register to add a comment.