A parallel plate capacitive displacement sensor has a plate area of $2 \mathrm{~cm}^{2}$. The air gap between the plates is decreased by $0.1$ mm from an initial value of $0.5$ mm. The percentage change in the capacitance value is $\_\_\_\_$ $\%$.
(Assume permittivity as $\epsilon_{0}=8.854 \times 10^{-12} \mathrm{~F} / \mathrm{m}$)
- $10.0$
- $14.1$
- $25.0$
- $30.0$
